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Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8504 Accepted Submission(s): 3931 You are given a number of case-sensitive strings of alphabetic characters, find the largest string X, such that either X, or its inverse can be found as a substring of any of the given strings.
The first line of the input file contains a single integer t (1 <= t <= 10), the number of test cases, followed by the input data for each test case. The first line of each test case contains a single integer n (1 <= n <= 100), the number of given strings, followed by n lines, each representing one string of minimum length 1 and maximum length 100. There is no extra white space before and after a string.
There should be one line per test case containing the length of the largest string found.
23ABCDBCDFFBRCD2roseorchid
Asia 2002, Tehran (Iran), Preliminary
//优化 #include #include #include #include using namespace std;const int N=100+10;int n,id,re,ilen;char c[N][N];int len[N];int main(){ int t,i,small,j,k,z,zz; bool ok; scanf("%d",&t); while(t--){ re=0; small=N; scanf("%d",&n); for(i=0;i 0;i--){ //枚举子串长度 for(j=0;re==0&&j+i-1 =0;z--) { //从右开始 for(zz=0;zz #include #include #include #include using namespace std;const int N=100+10;int n,id,re,ilen,rlen;char c[N][N];int len[N];int main(){ int t,i,small,j,k,z,zz; bool ok; scanf("%d",&t); while(t--){ re=0; rlen=0; small=N; scanf("%d",&n); for(i=0;i 0;j--) { //子串的长度 for(k=0;k =0;z--){ //从右开始 for(zz=0;zz
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